4x^2+64x+45=0

Solution for 4x^2+64x+45=0 equation:

4x^2+64x+45=0

a = 4; b = 64; c = +45;
Δ = b2-4ac
Δ = 642-4·4·45
Δ = 3376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3376}=\sqrt{16*211}=\sqrt{16}*\sqrt{211}=4\sqrt{211}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-4\sqrt{211}}{2*4}=\frac{-64-4\sqrt{211}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+4\sqrt{211}}{2*4}=\frac{-64+4\sqrt{211}}{8}
$